Position popup open in Angular Drop down button component

27 Apr 20242 minutes to read

Popup open position can be changed according to the requirement. Popup open position can be changed in open event by setting top and left for the popup element.

In the following example, the top position of the popup element is changed in open event.

app.component.ts

import { NgModule } from '@angular/core'
import { BrowserModule } from '@angular/platform-browser'
import { DropDownButtonModule } from '@syncfusion/ej2-angular-splitbuttons'
import { enableRipple } from '@syncfusion/ej2-base'



import { Component, ViewChild } from '@angular/core';
import { ItemModel, OpenCloseMenuEventArgs, DropDownButtonComponent  } from '@syncfusion/ej2-angular-splitbuttons';

@Component({
imports: [
        
        DropDownButtonModule
    ],


standalone: true,
    selector: 'app-root',
    template: `<div class="e-section-control">
                <!-- To render DropDownButton. -->
               <button ejs-dropdownbutton #dropdownbutton [items]='items' content='Clipboard' (open)='onOpen($event)'></button></div>`
})

export class AppComponent {
   @ViewChild('dropdownbutton')
   public dropdownbutton?: DropDownButtonComponent;
   // Initialize action items.
   public items: ItemModel[] = [
    {
        text: 'Cut'
    },
    {
        text: 'Copy'
    },
    {
        text: 'Paste'
    }];
    // To open popup in particular position.
    public onOpen (args: OpenCloseMenuEventArgs) {
       args.element.parentElement!.style.top = this.dropdownbutton!.element.getBoundingClientRect().top - args.element.parentElement!.offsetHeight +'px';
    }

}

main.ts

import { bootstrapApplication } from '@angular/platform-browser';
import { AppComponent } from './app.component';
import 'zone.js';
bootstrapApplication(AppComponent).catch((err) => console.error(err));